Solve this thing pls 3\left(q-7\right)=27

Question

Solve this thing pls

`3\left(q-7\right)=27`

Answer 1

• The value of q is 16

`\:`

Explanation:

So here, a equation is given and we are asked to solve the equation.

`\\ \dashrightarrow \sf \qquad3(q-7)=27 \\ \\`

For this, we have to use the Distributive property, which is :

• a(b + c) = ab + ac

`\\ \dashrightarrow \sf \qquad3q-21=27 \\ \\`

Transposing the constant term (-21) to the right side we get :

`\\ \dashrightarrow \sf \qquad3q=27 + 21 \\ \\`

Adding the like terms :

`\\ \dashrightarrow \sf \qquad3q=48 \\ \\`

Now, We'll divide both sides by 3 :

`\\ \dashrightarrow \sf \qquad (3q)/(3) = (48)/(3) \\ \\`

`\dashrightarrow \bf \qquad \: q=16 \\ \\`

Answer 2

• Solution of equation ( q ) = 16

Explanation:

In this question we have given an equation that is 3 ( q - 7 ) = 27 and we have asked to solve this equation that means to find the value of q .

Solution : -

`\quad \: \longmapsto \: 3(q - 7) = 27`

Step 1 : Solving parenthesis :

`\quad \: \longmapsto \:3q - 21 = 27`

Step 2 : Adding 21 on both sides :

`\quad \: \longmapsto \:3q - \cancel{ 21} + \cancel{21} = 27 + 21`

On further calculations we get :

`\quad \: \longmapsto \:3q = 48`

Step 3 : Dividing by 3 from both sides :

`\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}} = \cancel {(48)/(3) }`

On further calculations we get :

`\quad \: \longmapsto \: \pink{\boxed{\frak{q = 16}}}`

• Therefore, solution of equation ( q ) is 16 .

Verifying : -

Now we are very our answer by substituting value of q in the given equation . So ,

• 3 ( q - 7 ) = 27

• 3 ( 16 - 7 ) = 27

• 3 ( 9 ) = 27

• 27 = 27

• L.H.S = R.H.S

• Hence, Verified.

Therefore, our solution is correct .

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