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Find the 2 consecutive integers whose squares have a difference of 239

User Hsmit
by
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1 Answer

2 votes

Answer:

119 and 120

Explanation:

let the consecutive integers be n and n + 1 , then

(n + 1)² - n² = 239

n² + 2n + 1 - n² = 239

2n + 1 = 239 ( subtract 1 from both sides )

2n = 238 ( divide both sides by 2 )

n = 119

n + 1 = 119 + 1 = 120

the 2 integers are 119 and 120

as a check

120² - 119² = 14400 - 14161 = 239

User Saunik Singh
by
8.9k points

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