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A company produces batteries. On average,85% of all batteries produced are good. Each battery is tested before being dispatched, and the inspector correctly classifies the battery 90% of the time. A.What percentage of the batteries will be“classified as good”?B.What is the probability that a battery is defective given that it was classified as good?

User Jumbo
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Answer:

a) 78% of the batteries will be classified as good.

b) 1.92% probability that a battery is defective given that it was classified as good

Explanation:

A brief introduction about the conditional probability formula.

Conditional probability formula:


P(B|A) = (P(A \cap B))/(P(A))

In which

P(B|A) is the probability of event B happening, given that A happened.


P(A \cap B)[tex] is the probability of both A and B happening.</p><p>P(A) is the probability of A happening.</p><p><strong>A.What percentage of the batteries will be“classified as good”?</strong></p><p>85% are good, and of those, 90% are classified as good.</p><p>15% are not good and of those, 10% are classified as good.</p><p>Then</p><p>0.9*0.85 + 0.1*0.15 = 0.78</p><p>78% of the batteries will be classified as good.</p><p><strong>B.What is the probability that a battery is defective given that it was classified as good?</strong></p><p>Conditional probability.</p><p>A: Classified as good</p><p>B: Defective.</p><p>From a), P(A) = 0.78</p><p><strong>Intersection:</strong></p><p>Classified as good, but defective.</p><p>This is 10% of 15%. </p><p>[tex]P(A \cap B) = 0.1*0.15 = 0.015

Then:


P(B|A) = (P(A \cap B))/(P(A)) = (0.015)/(0.78) = 0.0192

1.92% probability that a battery is defective given that it was classified as good

User Robertpostill
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