Answer:
a) 78% of the batteries will be classified as good.
b) 1.92% probability that a battery is defective given that it was classified as good
Explanation:
A brief introduction about the conditional probability formula.
Conditional probability formula:

In which
P(B|A) is the probability of event B happening, given that A happened.
![P(A \cap B)[tex] is the probability of both A and B happening.</p><p>P(A) is the probability of A happening.</p><p><strong>A.What percentage of the batteries will be“classified as good”?</strong></p><p>85% are good, and of those, 90% are classified as good.</p><p>15% are not good and of those, 10% are classified as good.</p><p>Then</p><p>0.9*0.85 + 0.1*0.15 = 0.78</p><p>78% of the batteries will be classified as good.</p><p><strong>B.What is the probability that a battery is defective given that it was classified as good?</strong></p><p>Conditional probability.</p><p>A: Classified as good</p><p>B: Defective.</p><p>From a), P(A) = 0.78</p><p><strong>Intersection:</strong></p><p>Classified as good, but defective.</p><p>This is 10% of 15%. </p><p>[tex]P(A \cap B) = 0.1*0.15 = 0.015]()
Then:

1.92% probability that a battery is defective given that it was classified as good