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The identity (x2 + y2) = (x2 -y2) + (2xy)? can be used to generate Pythagorean triples. What

Pythagorean triple could be generated using x = 8 and y = 3?

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The identity (x2 + y2) = (x2 -y2) + (2xy)? can be used to generate Pythagorean triples-example-1
User Lutz
by
8.3k points

2 Answers

7 votes

Answer:

48,55,73

Explanation:

User SoulRayder
by
8.3k points
8 votes

Answer:

48, 55, 73

Explanation:

A Pythagorean triple are integers that can be entered in the Pythagorean theorem and be true

A common example is 3, 4, 5 because


3^(2) +4^(2) =5^(2)

So here, you want to plug in the 8 for the x in the equation and 3 for the y

Then, what you are looking for is when the equation looks like


a^(2) + b^(2) = c^(2)

So:


(8^(2)+3^(2))^(2) = (8^(2) - 3^(2))^(2) + (2(8)(3))^(2)

Simplify:


73^(2) = 55^(2) + 48^(2)

We can see that the numbers in here follow the pythagorean theorem, where c = 73, b = 55, and a = 48

So the triple is 48, 55, and 73

User Darryl Hebbes
by
8.2k points
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