Answer:
DeltaG0 = -(1) X 96485 X 0.034 = -3280.49 J /mole = -3.281 KJ / mole
Step-by-step explanation:
E0cell = E0cathode - E0anode
the cathode will be with more reduction potential and anode will have low reduction potential
E0cell = 0.254 - 0.220 = 0.034 V
Now
DeltaG0 = -nFE0cell
E0cell = 0.034 V
F = 96485 C
n = 1
Putting values
DeltaG0 = -(1) X 96485 X 0.034 = -3280.49 J /mole = -3.281 KJ / mole