Given Information:
Acceleration = a = 3.5×10⁵g
Gravitational constant = g = 9.8 m/s²
Distance from axis of rotation = r = 2.0 cm = 0.02 m
Required Information:
Angular speed = ω = ?
Answer:
Angular speed = ω = 1.31×10⁴ rad/s
Step-by-step explanation:
We know that the centripetal acceleration is given by
a = v²/r
The relationship between linear and angular speed is given by
v = ωr
Where ω is the angular speed
So the acceleration becomes
a = (ωr)²/r
a = ω²r²/r
a = ω²r
Re-arrange for ω
ω² = a/r
ω = √(a/r)
The acceleration is
a = 3.5×10⁵g
where g is the gravitational constant
a = 3.5×10⁵*9.81
a = 3.434×10⁶ m/s²
Finally, the required angular speed is
ω = √(3.434×10⁶/0.02)
ω = 1.31×10⁴ rad/s