Question

suppose the normal distribution has a mean of 98 and a standard deviation of 6. what is P(x < 92)? 0.16 0.025 0.84 0.975

Answer 1

0.16

Explanation:

Answer 2

P(x < 92) is 0.16

Explanation:

We are given that the normal distribution has a mean of 98 and a standard deviation of 6.

Mean =
`\mu = 98`

Standard deviation =
`\sigma = 6`

We are supposed to find P(x < 92)

Formula :
`Z=(x-\mu)/(\sigma)`

`Z=(92-98)/(6)`

Z=-1

Refer the z table for p value

So,p value = 0.1587

So, P(x < 92) is 0.16

Option A is true

Hence P(x < 92) is 0.16