Answer:
P(x < 92) is 0.16
Explanation:
We are given that the normal distribution has a mean of 98 and a standard deviation of 6.
Mean =
![\mu = 98](https://img.qammunity.org/2021/formulas/mathematics/college/49fp8m3m3hkik87lyuyumpln1mlmnw00qp.png)
Standard deviation =
![\sigma = 6](https://img.qammunity.org/2021/formulas/mathematics/college/3mtc9bpkrpbvinsu8o3zs0ubpbcb7h7akc.png)
We are supposed to find P(x < 92)
Formula :
![Z=(x-\mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4jbyrm14nh8wz5n25atg56yn1mof3pup4y.png)
![Z=(92-98)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jirxh2n2meqmjt97pjmpdm5mi8jfiv6r92.png)
Z=-1
Refer the z table for p value
So,p value = 0.1587
So, P(x < 92) is 0.16
Option A is true
Hence P(x < 92) is 0.16