Question

a 22.44 g sample of metal absorbs 180.8 J of hear , upon which the temprature of the sample increases from 21.1 °C to 45.0 °C . what is the specific heat of that metal

Answer 1

The specific heat of the metal is
`0.337\ J/g^(\circ) C`.

Step-by-step explanation:

We have,

Mass of sample is 22.44 g

It absorbs 180.8 J of heat.

The temperature of the sample increases from 21.1 °C to 45.0 °C

Initial temperature is 21.1 °C and final is 45.0 °C.

Heat absorbed in terms of specific heat is given by :

`Q=mc\Delta T\\\\c=(Q)/(m\Delta T)\\\\c=(180.8)/(22.44* (45-21.1))\\\\c=0.337\ J/g^(\circ) C`

So, the specific heat of the metal is
`0.337\ J/g^(\circ) C`.