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Solve the equation 2sin(x) + 1= 0

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Answer:

Explanation:

+ First, we write 2sin(x) = -1 (add -1 for both sides)

Then sin(x) = -1/2 (divide both sides by 2).

+ And we know that -1/2 = sin( -pi/6)

So sin(x) = sin (-pi/6)

that implicite:


x=-(\pi )/(6) + 2k\pi\\x= \pi - (-(\pi)/(6) )+ 2k\pi= (7\pi)/(6) +2k\pi

Hope it useful for you.

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