36. (Higher) 2Mg + O2 → 2Mgo. Limiting reactant is Mg (4 mol). What is the amount of product (in mol)? PLEASE HELP ME HOW TO WORK THESE OUT!!

Alfons asked Nov 1, 2023

532,027 views

4 votes

36. (Higher) 2Mg + O2 → 2Mgo. Limiting reactant is Mg (4 mol). What is the amount of

product (in mol)? PLEASE HELP ME HOW TO WORK THESE OUT!!

Alfons asked Nov 1, 2023

2.5k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

14 votes

Answer:

4 mol MgO

Step-by-step explanation:

convert the limiting reactant to product by using dimensional analysis in order to see how many moles total can be created of the product

4 mol Mg x
(2 mol MgO)/(2 mol Mg) = 4 mol MgO

3.4k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers