36. (Higher) 2Mg + O2 → 2Mgo. Limiting reactant is Mg (4 mol). What is the amount of product (in mol)? PLEASE HELP ME HOW TO WORK THESE OUT!!

Alfons asked Nov 1, 2023

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4 votes

36. (Higher) 2Mg + O2 → 2Mgo. Limiting reactant is Mg (4 mol). What is the amount of

product (in mol)? PLEASE HELP ME HOW TO WORK THESE OUT!!

Alfons asked Nov 1, 2023

2.5k points

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14 votes

Answer:

4 mol MgO

Step-by-step explanation:

convert the limiting reactant to product by using dimensional analysis in order to see how many moles total can be created of the product

4 mol Mg x
(2 mol MgO)/(2 mol Mg) = 4 mol MgO

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