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13 votes
13 votes
Calculate the ph of 0,24 m of kch3coo.? ​

User Jabamataro
by
2.8k points

1 Answer

16 votes
16 votes

Answer:

Correct option is A)

[H

+

]=

KaC

=

1.8×10

−6

=1.34×10

−3

pH=−log[H

+

]

=2.88

Step-by-step explanation:

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User Sergo Pasoevi
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