Question

A briefcase has a three- digit lock code that doesn't include zero as a digit. What is the probability that the lock code consists of all even digits if the same digit is not used more than once.

Answer 1

1/21.

Explanation:

There are 9 digits and the total number of permutations of 3 from 9 is 9P3

= 9!/6! = 504.

There are 4 even digits so the number of permutations of 3 from these 4 is 4! (4-3)! = 4*3*2 = 24.

So the required probability = 24/504

= 1/21.

Answer 2

A) 24 out of 504

Explanation:

Edge2020