Question

Kana is practicing her golf swing at the driving range. Her first hit can be described by the displacement

(distance and direction) vector d = (55,5). Her second hit can be described by the displacement vector
d2 = (75, 10).

Answer 1

20.6 is the difference from the first to second hit

Answer 2

The distance difference between those swings is 20.6, approximately.

Explanation:

To find the difference between the distance of each swing, we need to subtract vectors and find the module of the resulting vector.

`d_(1)=(55,5)` represents the first swing.

`d_(2)=(75,10)` represents the second swing.

In the image attached, the difference is shown by vector
`w`.

Mathematically, this displacement is defined

`w=d_(2)-d_(1)`

`w=(75,10)-(55,5)\\w=(75-55,10-5)\\w=(20,5)`

Now, we find its module

`|w|=\sqrt{20^(2) +5^(2) }=√(400+25)=√(425)\\ |w| \approx 20.6`

Therefore, the distance difference between those swings is 20.6, approximately.