Question

Mass M1 = 2.25 kg is at the end of a rope that is 2.00 m in length. The initial angle with respect to the vertical is 60.0° and M1 is initially at rest. Mass M1 is released and strikes M2 = 4.50 kg (also at rest) exactly horizontally. The collision is elastic. After the collision, mass M2 is moving on a frictionless surface but later runs into a rough patch with a coefficient of friction = 0.175 for both kinetic and static friction.

At the end of the rough patch, the object is again on a frictionless surfave and is stopped by a spring with spering constant equal to k=50.0 N/m. Calculating the following
a. Velocities of Masses M1 and M2 after collision
b. The amount the spring is compressed while stopping mass M2
c. What Maximum height after collision does mass M1 obtain?

Answer 1

a) V1 = -1.49 m/s

V2= 2.98 m/s

b) 2.54 m

c) 0.111 m

Step-by-step explanation:

The pictures attached below explains all about the three questions.

page 1 answers question 1

page 2 answers question 2

page 3 answers question 3

I hope it helps you. Thank you