Question

What is the probability of choosing a gray button not replacing it and choosing gray again?

Answer 1

the probability of choosing a gray button is 3/5

after putting it back the probability remains the same, so 3/5 for both answers

Answer 2

`\sf (3)/(10)` = 0.3 - 30%

Explanation:

`\sf Probability\:of\:an\:event\:occurring = (Number\:of\:ways\:it\:can\:occur)/(Total\:number\:of\:possible\:outcomes)`

Given:

• Grey buttons = 3
• White buttons = 2
• Total buttons = 5

`\sf P(gray) = \frac35`

If the button is not replaced, there are now:

• Grey buttons = 3 - 1 = 2
• White buttons = 2
• Total buttons = 5 - 1 = 4

`\sf P(gray) = \frac24=\frac12`

Therefore,

`\sf P(gray)\:AND\:P(gray)= \frac35 * \frac12=(3)/(10)`