Answer:
Of the 16 possible experimental outcomes, 4 outcomes result in exactly 1 success.
The probability of a determined sample point with an outcome of one success is P=0.0992.
Explanation:
We have a proportion of success (the selection of a manager who reads e-mail in the bathroom) of p=0.18.
The sample size is n=4.
We can model this as a binomial random variable.
The sample space is [0, 1, 2, 3, 4].
The possible outcomes for x=0 (that is no manager in the sample reads email in the bathroom) can be calculated as:

The same way we can calculate all the other possible outcomes:

The sum of this outcomes is 16 possible outcomes. Of the 16 possible experimental outcomes, 4 outcomes result in exactly 1 success.
The probability of an outcome with 1 success is the product of p (the one that reads email) times (1-p)^3 (the other 3 that do not read emails in the bathroom):
