Question

Easy question

Find the straight line equations

1) Passing through two points: (1,2) and (2,4)
2) Passing through a point of (-2,6) and parallel to the straight line of 3x-4y-6=0

Answer 1

1) y = 2x

2) y = (3/4)x + 15/2

Explanation:

1) slope: (4-2)/(2-1) = 2/1 = 2

y = 2x + c

2 = 2(1) + c

c = 0

y = 2x

2) 3x - 4y - 6 = 0

4y = 3x - 6

y= (3/4)x - 3/2

slope: 3/4

y = (3/4)x + c

6 = (3/4)(-2) + c

c = 6 + 3/2

c = 15/2

y = (3/4)x + 15/2