Question

(10x^3y^-2/5x^-3y^4)^-3, x≠0, y≠0

Answer 1

Answer: d or y^6/8x^18

Explanation:

Answer 2

`(y^(18))/(8x^(18))`

Explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

(a^b)^c = a^(bc)

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Your expression simplifies as follows:

`\left((10x^3y^(-2))/(5x^(-3)y^4)\right)^(-3)=(2x^(3-(-3))y^(-2-4))^(-3)=(2x^6y^(-6))^(-3)\\\\=(2^(-3))x^(6(-3))y^((-6)(-3))=(1)/(8)x^(-18)y^(18)\\\\=\boxed{(y^(18))/(8x^(18))}`