Question

Help Please!!!!

What is the distance from the hazard buoy P to the southern landmark L2? Use this formula: d^2=(DL2)^2+(PD)^2 , where d is the distance from P to L2, DL2 is the distance from D to L2, and PD is the distance from P to D. Round to the nearest foot. (5 points)

DL2 = 600ft
PD = 700ft

Answer 1

922 ft

Explanation:

`d^(2)=PD^(2)+D_(2)L^(2)\\\ \ \ \ \\ =\ 600^(2)+700L^(2)\\\ \ \ \ \\ =\ 850000\\\\\text \\then\\d = √(850000) =921.954445729289\\\\\text then\\d\ \approx922`