A 500 mL piston has a gas mixture inside at a pressure of 15.0 atm. What volume would the piston have if the pressure increased to 30.0 atm?

Question

asked May 18, 2021 170k views

1 Answer

Pebble Unit · Answer 1 · 2021-05-23T23:43:35+0000

Answer:

The volume of the piston would be 250 mL.

Step-by-step explanation:

Volume of the piston,
$V_1=500\ mL$

Pressure,
$P_1=15\ atm$

Let
V_2 is the volume of piston if the pressure increased to 30.0 atm.

It is based on Boyle's law. It is given by:

$(V_1)/(V_2)=(P_2)/(P_1)\\\\V_2=(V_1P_1)/(P_2)\\\\V_2=(500* 15)/(30)\\\\V_2=250\ mL$

So, the volume of the piston would be 250 mL.