Question

A 500 mL piston has a gas mixture inside at a pressure of 15.0 atm. What volume would the piston have if the pressure increased to 30.0 atm?

Answer 1

The volume of the piston would be 250 mL.

Step-by-step explanation:

Volume of the piston,
`V_1=500\ mL`

Pressure,
`P_1=15\ atm`

Let
`V_2` is the volume of piston if the pressure increased to 30.0 atm.

It is based on Boyle's law. It is given by:

`(V_1)/(V_2)=(P_2)/(P_1)\\\\V_2=(V_1P_1)/(P_2)\\\\V_2=(500* 15)/(30)\\\\V_2=250\ mL`

So, the volume of the piston would be 250 mL.