Question

A glass windowpane in a home is 0.62 cm thick and has dimen- sions of 1.0 m 3 2.0 m. On a certain day, the indoor temper- ature is 25°C and the outdoor temperature is 0°C. (a) What is the rate at which energy is transferred by heat through the glass? (b) How much energy is lost through the window in one day, assuming the temperatures inside and outside remain constant?

Answer 1

Step-by-step explanation:

Thermal conductivity of glass pane = .8 W / m K

For conduction of heat , the formula is as follows

Q =
`(kA(T_1 - T_2 )t)/(d )` ; Q is heat conducted in time t by a medium of thickness d , area of cross section A and ( T₁ - T₂ ) is the temperature difference .

Putting the values in the equation

Q =
`(.8 *32*(25 - 0 )*1)/(.0062 )`

= 103225.8 W

b )

energy lost in one day

= 103225.8 x 24 x 60 x 60

= .89187 x 10¹⁰ J .