Question

At what temperature would 2. 10 moles of N2 gas have a pressure of 2. 25 ATM and in 25. 0 L tank?

Answer 1

About 326 K.

Step-by-step explanation:

Recall the ideal gas law:

`\displaystyle PV = nRT`

Where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

Because we want to solve for temperature T:

`\displaystyle T = (PV)/(nR)`

Substitute and evaluate. R has a value of 0.08206 L-atm/mol-K:

`\displaystyle \begin{aligned} T & = \frac{(2.25\text{ atm})(25.0\text{ L})}{(2.10\text{ mol})\left(\frac{0.08206\text{ L - atm}}{\text{mol - K}}\right)} \\ \\ & = 326\text{ K}\end{aligned}`

In conclusion, the temperature of the gas will be about 326 K.