Register
Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of candy cost the same amount. If the total cost for all four friends was $ 58.00,
217k views
0 votes
Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of candy cost the same amount. If the total cost for all four friends was $ 58.00, what was the price of one (1) box of candy.

User Bhoward
by
8.6k points

2 Answers

7 votes

Answer:

$7

Explanation:

58-7.50x4=30 58-30=28/4=7

User George Fisher
by
8.6k points
4 votes
Subtract the cost of tickets from the total. 4x7.5=30. 58-30=28. Eight boxes of candy were purchased in total. Use c to represent candy. 8c=28. Finally, divide both by 8. 28/8= 3.5. The answer is $3.50.
User Harold Chan
by
8.8k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!