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Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of candy cost the same amount. If the total cost for all four friends was $ 58.00,
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Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of candy cost the same amount. If the total cost for all four friends was $ 58.00, what was the price of one (1) box of candy.

User Bhoward
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2 Answers

7 votes

Answer:

$7

Explanation:

58-7.50x4=30 58-30=28/4=7

User George Fisher
by
3.8k points
4 votes
Subtract the cost of tickets from the total. 4x7.5=30. 58-30=28. Eight boxes of candy were purchased in total. Use c to represent candy. 8c=28. Finally, divide both by 8. 28/8= 3.5. The answer is $3.50.
User Harold Chan
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3.8k points
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