Answer:
![85in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jvogimxaghih2mj3k6jzepmos4xkka0nkh.png)
Explanation:
to find the surface area we need to find the followng areas:
- area of a triangle and multiply it by 4 (because there are 4 triangles)
And once we have those areas, we add them to find the surface area.
Area of the square:
the formula to find the area of a square is:
![a_(square)=l^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3488sq88esmzv5r1g2a599xjgmehfzmizn.png)
where
is the length of the side:
![l=5in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bsw1l130vexfpijezwq9yboumqgpd5hrf9.png)
thus the area of the square is:
![a_(square)=(5in)^2\\a_(square)=25in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qed14vqejynv8fuhiugf0fp4ld3tmqqr3l.png)
Area of the triangles:
the are of 1 triangle is given by
![a_(triangle)=(b*h)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jt8d79mc2kbtk66d6v1cofgfo1ikj5jhs7.png)
where
is the base of the triangle:
(the base of the triangle is the side of the square)
and
is the height of the triangle:
![h=6in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a50jha5xhlah3jsgl6p6792ndygp5wyj30.png)
thus, the area of 1 triangle is:
![a_(triangle)=((5in)*(6in))/(2)\\ a_(triangle)=(30in^2)/(2)\\ a_(triangle)=15in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n7aetybydw4l22xs5ek9pnex911xatj6zp.png)
the area of the 4 triangles is (we multiply by 4):
![a_(4-triangles)=4(15in^2)\\a_(4-triangles)=60in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/19ugatm1yl6z624wjmmzrrpuu671m4irmo.png)
finally we add the area of the square and the area of the 4 triangles to find the total surface area:
![Surface=25in^2+60in^2\\Surface=85in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pikggaygim35lw57e74is3t4uqgreptuop.png)