Question

Help I’ll do anything just help

Answer 1

`1) {n}^(2) - 81 \\ (n - 9)(n + 9)`

`2) \: \: {a}^(2) - 121 \\ (a - 11)(a + 11)`

`3) \: \: {n}^(2) - 16 \\ (n - 4)(n + 4)`

`4) \: \: 9 {x}^(2) - 144 \\ {3}^(2) {x}^(2) - {12}^(2) \\ (3x - 12)(3x + 12)`

`5) \: 2 {x}^(2) - 9 \\ (2x - 3)(x + 3)`

`6) \: \: 4 {w}^(2) - 9 \\ {2}^(2) {w}^(2) - {3}^(2) \\ (2w + 3)(2w - 3)`

`7) \: \: 4 {n}^(2) - 1 \\ {2}^(2) {n}^(2) - {1}^(2) \\ (2n + 1)(2n - 1)`

`8) \: \: 1 - 16 {x}^(2) \\ {1}^(2) - {4}^(2) {x}^(2) \\ (1 - 4x)(1 + 4x)`

`9) \: \: {x}^(2) - {y}^(2) \\ (x - y)(x + y)`

`10) \: \: 9 - {c}^(2) \\ {3}^(2) - {c}^(2) \\ (3 - c)(3 + c)`

`11) \: \: {n}^(2) - 25 \\ {n}^(2) - {5}^(2) \\ (n + 5)(n - 5)`

`13)49 - 4 {a}^(2) \\ {7}^(2) - {2}^(2) {a}^(2) \\ (7 - 2a)(7 + 2a)`

`14) {a}^(2) {b}^(2) - {c}^(4) \\ (ab - {c}^(2) )(ab + {c}^(2) )`

`15) \: \: 4 {x}^(2) {y}^(2) - 9 {z}^(2) \\ {2}^(2) {x}^(2) {y}^(2) - {3}^(2) {z}^(2) \\ (2xy - 3z)(2xy + 3z)`

hope this helps

sorry, I don't know how solve the 12th one.

thanks.