What is the area of a rectangle with vertices (2, 3), (9, 3), (9, Negative 2), and (2, Negative 2)? square units

Question

asked Feb 5, 2021 128k views

2 Answers

YuvrajsinhJadeja · Answer 1 · 2021-02-11T02:06:02+0000

Answer:

Area of the rectangle =
$35\,\,units^2$

Explanation:

Area of the Rectangle= Product of the two Unequal sides

Finding the two unequal sides of the rectangle using the distance formula:

For the coordinates:

A(2,3) B(9,3) C(9,-2) D(2,-2)

Using Distance formula:

AB=

$=√((9-2)^2+(3-3)^2) \\\\=√(7^2+0) \\\\=√(49)\\\\ =7\,\,units$

Similarly, BC= 5 units

Area of the rectangle is:

$=7* 5\\\\=35\,\,units^2$