Question

What is the area of a rectangle with vertices (2, 3), (9, 3), (9, Negative 2), and (2, Negative 2)? square units

Answer 1

The answer is definitely 35

Answer 2

Area of the rectangle =
`35\,\,units^2`

Explanation:

Area of the Rectangle= Product of the two Unequal sides

Finding the two unequal sides of the rectangle using the distance formula:

For the coordinates:

A(2,3) B(9,3) C(9,-2) D(2,-2)

Using Distance formula:

AB=

`=√((9-2)^2+(3-3)^2) \\\\=√(7^2+0) \\\\=√(49)\\\\ =7\,\,units`

Similarly, BC= 5 units

Area of the rectangle is:

`=7* 5\\\\=35\,\,units^2`