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What is the measure of arc AD?

Angle ABD measures (4x + 10). Angle ACD measures

(5x - 2)

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1 Answer

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Answer:

116°

Explanation:

Given that :

∠ ABD measures (4x + 10)

∠ ACD measures (5x - 2)

Then

∠ABD = ∠ACD ( rule : angle by same chord AD )

∠ABD = (4x + 10)°

∠ACD = (5x - 2)°

so we can as well say that :

(4x + 10)° = (5x - 2)°

4x - x = -10 -2

- x = - 12

x = 12

∠ABD = (4x + 10)°

= ( 4 × 12 + 10)°

= 58°

∠ACD = (5x - 2)°

= ( 5 * 12 - 2)°

= 58°

∠AOD = 2∠ABD = 2∠ACD ( since angle by arc AD at center is twice the angle by same arc AC in other arc segment)

∠AOD = 2 × 58°

∠AOD = 116°

Measure of arc AD = 116°

User Midhilaj
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