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The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?

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User Chbu
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1 Answer

4 votes

Answer:

The radius of hole is 5 feet

Explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole =
(1)/(3) \pi r^2 h

So, Volume of conical hole =
(1)/(3) \pi * r^2 * 9

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So,
(1)/(3) \pi * r^2 * 9=75 \pi


(1)/(3) * r^2 * 9=75


r^2=(75 * 3)/(9)


r=\sqrt{(75 * 3)/(9)}

r=5

Hence The radius of hole is 5 feet

User Panos Rontogiannis
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