Question

In triangle ABC, a=10, b=8, and sinB=(3/4). Find sinA

Answer 1

15/16

Explanation:

To find the value of Sin A can be found using the sine rule. the rule states that the ratio of the length facing an angle in a triangle to the sine of the angle is constant. As such,

a/Sin A = b/Sin B = c/Sin C

Where is a is the side facing angle A, b is the side facing angle B and c is the side facing angle C.

Hence,

8/(3/4) = 10/Sin A

Sin A = 3 * 10 / (8 * 4)

= 30/32

= 15/16