Question

Ivan is playing a skee-ball game. Different points are awarded depending on which hole the ball goes through. When the ball goes in the smallest hole, it is worth 100 points. When it goes in the bigger hole, it is worth 10 points, and when it does not go in either hole, it is worth 1 point. Ivan earned 352 points in the last game.

Which combination will result in a score greater than his current score?

2 balls in the smallest hole, and 8 balls in the bigger hole
4 balls in the smallest hole, and 6 balls in neither hole
3 balls in the smallest hole, 4 balls in the bigger hole, and 3 balls in neither hole
3 balls in the smallest hole, 3 balls in the bigger hole, and 4 balls in neither hol

Answer 1

Answer: 4 balls in the smallest hole and 8 balls in the bigger hole

Explanation: Since 1 ball in the smallest hole in worth 100 points and 4 balls in the smallest hole, then we multiply 4 by 100 to get 400. And also, every ball that doesn't make either one of the holes, it counts as 1 point , so we multiply 1 by 6 to get 6. Finally add up 400 and 6 to get 406, more than his current score.