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How many grams of NaCI are present in 11.00 moles

User JeePakaJP
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1 Answer

6 votes

Answer: 642.93 g of NaCl

Step-by-step explanation:

11.00 mol NaCl x __58.448 g__ = 642.928 g of NaCl

1 mol NaCl

I would round to 642.93 g of NaCl, but round to however many significant figures asked for.

My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.

How many grams of NaCI are present in 11.00 moles-example-1
User BountyHunter
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