Question

A balloon at 30.0°C has a volume of 222 mL. If the temperature is

increased to 53.1°C and the pressure remains constant, what will the new volume be, in ml?​

Answer 1

Answer : The new volume will be, 238.9 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1\text{ and }T_1` are the initial volume and temperature of the gas.

`V_2\text{ and }T_2` are the final volume and temperature of the gas.

We are given:

`V_1=222mL\\T_1=30.0^oC=(30.0+273)K=303K\\V_2=?\\T_2=53.1^oC=(53.1+273)K=326.1K`

Putting values in above equation, we get:

`(222mL)/(303K)=(V_2)/(326.1K)\\\\V_2=238.9mL`

Therefore, the new volume will be, 238.9 mL