Question

A basketball has a volume of 7.1 L at a temperature of 300 k what is the volume of the basketball at 273 k

Answer 1

According to Charles's law, the volume of a gas is directly proportional to its temperature at constant pressure. Using the formula V1/T1 = V2/T2, we can calculate the volume of the basketball at 273 K.

Step-by-step explanation:

According to Charles's law, the volume of a gas is directly proportional to its temperature at constant pressure. We can use the formula V1/T1 = V2/T2 to solve this problem.

Given:

• V1 = 7.1 L
• T1 = 300 K
• T2 = 273 K
• V2 = ?

Using the formula, we can substitute the values and solve for V2:

V1/T1 = V2/T2

7.1 L / 300 K = V2 / 273 K

Cross multiplying, we get:

V2 = (7.1 L * 273 K) / 300 K

V2 = 6.46 L (rounded to two decimal places)

Answer 2

The volume of the basketball at 273 K is 6.461 L

Step-by-step explanation:

When the gas temperature increases, the molecules move faster and take less time to reach the walls of the container. This means that the number of crashes per unit of time will be greater. That is, there will be an increase in the pressure inside the container and the volume will increase.

Charles's Law is a gas law that relates the volume and temperature of a certain amount of gas at constant pressure. So, the ratio between volume and temperature will always have the same value:

`(V)/(T) =k`

In this case, you know:

• V1= 7.1 L
• T1= 300 K
• V2= ?
• T2= 273 K

Replacing:

`(7.1 L)/(300K) =(V2)/(273 K)`

Solving:

`V2=(7.1 L)/(300K) *273 K`

V2= 6.461 L

The volume of the basketball at 273 K is 6.461 L