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Write an equation that is perpendicular to y=4x- 10 and goes through the point (4,2)

1 Answer

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Answer:

y = (-1/4)x + 3

Explanation:

The slope of our equation is 4, so to find the slope of the perpendicular equation, we have that:

m1 * m2 = -1

Where m1 is the slope of the first equation and m2 is the slope of the perpendicular equation.

So, we have that:

4 * m2 = -1

m2 = -1/4

So the second equation is y = (-1/4)x + b

If the second equation goes through the point (4,2), for x = 4 we have y = 2, then:

2 = (-1/4)*4 + b

2 = -1 + b

b = 3

So the perpendicular equation is:

y = (-1/4)x + 3

User Nikoloza
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