Question

How many moles of P4 will form when 1 mole of Ca3(PO4)2 reacts with 3 moles of SiO2 and 2 moles of C? Ca3(PO4)2 + 6 SiO 2 + 10 C → P 4 + 6 Ca SiO 3 + 10 CO?

Answer 1

0.5

Step-by-step explanation:

We are given the moles of two reactants, so this could be a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

2Ca₃(PO₄)₂ + 6SiO₂ + 10C → P₄ + 6CaSiO₃ + 10CO

n/mol: 1 3

Calculate the moles of P₄ that can be formed from each reactant :

1. From Ca₃(PO₄)₂

`\text{Moles of P}_(4) = \text{1 mol Ca$_(3)$(PO}_(4))_(2) * \frac{\text{1 mol P}_(4)}{\text{2 mol Ca$_(3)$(PO}_(4))}_(2) = \text{0.5 mol P}_(4)`

2. From SiO₂

`\text{Moles of P}_(4) = \text{3 mol SiO}_(2) * \frac{\text{1 mol P}_(4)}{\text{6 mol SiO}_(2)} = \text{0.5 mol P}_(4)`

Each reactant forms 0.5 mol of P₄.