Answer:
23388 years
Step-by-step explanation:
Now we have to use the formula;
0.693/t1/2 = 2.303/t log No/N
Where
t1/2 = half life of the C-14 = 5700
t= age of the sample
No= radioactive material in a modern sample = No
N= radioactive material in a sample being studied. = 0.81No( since the amount N= No-0.19No)
Hence;
0.693/5700 = 2.303/t log No/0.81No
0.693/5700 = 2.303/t log 1/0.81
0.693/5700 = 2.303/t × 1.235
0.693/5700= 2.844/t
1.216×10^-4= 2.844/t
t= 2.844/1.216×10^-4
t= 23388 years