Glven: AABC with altitude h shown in the diagram. The altitude is perpendicular to BC.
Prove: Area of AABC = 1/2ab sin(C)
By the definition of the (sine ratio, area of triangle, or perimeter of triangle) , the area of ABC is 1/2 ah, then, sin (C)h/b bye the definition of the sine ratio. Using the (division property, multiplication property, substitution property,) bsin(C) = H. Lastly A= 1/2absin(C) by the (simplification, division property, multiplication property, substitution property)