Question

How many liters are in 3.36 grams of F2 gas at STP

Answer 1

To find the number of liters in 3.36 grams of F2 gas at STP, you can use the molar volume of gases at STP, which is 22.4 L/mol. By setting up a proportion, you can calculate the number of moles of F2 gas, and then use the molar volume to find the number of liters.

Step-by-step explanation:

To determine the number of liters in 3.36 grams of F2 gas at STP, we can use the molar volume of gases at STP, which is 22.4 L/mol.

The molar mass of F2 is 38.0 g/mol, which means that 1 mole of F2 gas has a mass of 38.0 grams.

Therefore, we can set up a proportion to find the number of moles of F2 gas in 3.36 grams:

3.36 grams F2 × (1 mol F2 / 38.0 grams F2) = 0.0884 moles F2

Now, we can use the molar volume to find the number of liters:

0.0884 moles F2 × (22.4 L / 1 mol) = 1.98 liters

Answer 2

Volume = 3.98L

Step-by-step explanation:

Volume = ?

Mass = 3.36g

Pressure at STP = 1atm

Temperature at STP = 273.15k

Molarmass = 18.99g/mol

R = 0.082J/mol.K

From ideal gas equation

PV = nRT

P = pressure

V = volume the gas occupies

n = number of moles,

R = ideal gas constant

T = temperature of the gas

PV = nRT

Number of moles = mass / molarmass

n = 3.36 / 18.99

n = 0.1769 moles

PV = nRT

Solve for V

V = nRT/ P

V = (0.1769 * 0.082 * 273.15) / 1

V = 3.96L

The volume the gas occupies is 3.96L