Question

Calculate the energy released in each of the following fusion reactions. Give your answers in MeV. (a) 2H + 3H → 4He + n 17.54 Correct: Your answer is correct. MeV (b) 4He + 4He → 7Be + n 18.997 Correct: Your answer is correct. MeV (c) 2H + 2H → 3He + n 3.26 Correct: Your answer is correct. MeV (d) 2H + 1H → 0γ + 3He 4.4856 Incorrect: Your answer is incorrect. MeV (e) 2H + 2H → 3H + 1H 4.075 Correct: Your answer is correct. MeV

Answer 1

a) E = 17.55 MeV

b) E = 18.99 MeV

c) E = 3.29 MeV

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e) E = 4.075 MeV

Step-by-step explanation:

Energy Released,
`E = \triangle M * 931.5`

`\triangle M = \sum M_(product) - \sum M_(reactant)`

Mass of 1H,
`M_(H) = 1.007823`

Mass of 2H,
`M_(2H) = 2.0141u`

Mass of 3H,
`M_(3H) = 3.016 u`

Mass of Helium,
`M_(4He) = 4.002602u`

Mass of Beryllium,
`M_(7Be) = 7.01693 u`

Mass of neutron,
`M_(n) = 1.008664 u`

a)
`2H + 3H \rightarrow 4He + n`

`\triangle M = (4M_(He) + M_(n) ) - (2M_(H) + 3 M_(H) )\\\triangle M = ( 4.0026 + 1.008664) - (2.0141 + 3.016 )\\\triangle M = -0.01884u`

Energy released,

`E = -0.01884 * 931.5\\E = -17.55 Mev`

Energy released = 17.55 MeV

b)
`4He + 4He \rightarrow 7Be + n`

`\triangle M = (M_(7Be) + M_(n) ) - (M_(4He) + M_(4He) )\\\triangle M = ( 7.01693 + 1.008664) - (4.002602 + 4.002602 )\\\triangle M = 0.02039 u`

Energy released,

`E = 0.02039 * 931.5\\E = 18.99 Mev`

c)
`2H + 2H \rightarrow 3 He` + n

`\triangle M = (M_(3He) + M_(n) ) - (M_(2H) + M_(2H) )\\\triangle M = ( 3.016 + 1.008664) - (2.0141 + 2.0141 )\\\triangle M = -0.003536 u`

Energy released,

`E = -0.003536 * 931.5\\E = -3.29 Mev`

E = 3.29 MeV(Energy is released)

d) You can use the methods applied for the other parts to solve this, the equation is not properly written

e)
`2H + 2H \rightarrow 3H + 1H`

`\triangle M = (M_(3H) + M_(1H) ) - (M_(2H) + M_(2H) )\\\triangle M = ( 3.016 + 1.007825) - (2.0141 + 2.0141 )\\\triangle M = -0.00435 u`

`E = -0.00435 * 931.5\\E =-4.075 Mev`

E = 4.075 MeV ( Energy is released)