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In horses, black coats (B) are dominant to chestnut coats (b). Trotting (1) is also dominant to pacing (t). If a homozygous black pacer

(BBtt) is mated to a homozygous chestnut trotter (bbTT), what percent of the offspring will have bbtt?

User Bkev
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1 Answer

2 votes

Answer:

0%

Step-by-step explanation:

Both alleles appear homozygous dominant in one of the parents, therefore if you cross them in a punnett square all will be heterozygous.

User Smilin Brian
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