Answer:
24.52 mL
Step-by-step explanation:
Data obtained from the question include:
Number of mole of N2 = 0.52 mole
Volume of N2 = 17L
Number of mole of CO2 = 0.750 mol
Next, we need to obtain the volume of 0.750 mole N2.
This is illustrated below:
Initial volume (V1) = 17L
Initial mole (n1) = 0.52 mole
Final volume (V2) =.?
Final mole (n2) = 0.750 mole
PV = nRT
Divide both side by n
PV/n = RT
Divide both side by P
V/n = RT/P
Since pressure (P) and temperature (T) are constant, then
V/n = constant
V1/n1 = V2/n2
With the above equation, we can obtain the new volume of N2 as follow:
V1/n1 = V2/n2
17/0.52 = V2/0.75
Cross multiply to express in linear form
0.52 x V2 = 17 x 0.75
Divide both side by 0.52
V2 = (17 x 0.75) /0.52
V2 = 24.52 mL.
The volume occupied by 0.75 mole of N2 is 24.52 mL.
Since 0.750 mole of CO2 is under the same temperature and pressure as 0.750 mole of N2, they will both occupy the same volume.
Therefore, 0.750 mole of CO2 will occupy 24.52 mL