Question

Once again assistance is needed. Help!!!!

Answer 1

D

Explanation:

Given

f(x) =
`((x+2)(x-1))/((x-3)(x+2))` ← cancel (x + 2) on the numerator/ denominator

This creates a discontinuity ( a hole ) at x = - 2

f(x) =
`(x-1)/(x-3)`

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x - 3 = 0 ⇒ x = 3 ← excluded value

Thus domain is x → D

Answer 2

D

Explanation:

hope this helps