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3 votes
3x + 8y = 28
3x + 2y = 4
Find both the x and y coordinates

User Lambmj
by
7.9k points

2 Answers

4 votes

If you subtract the two equations you get


\underbrace{(3x + 8y)-(3x + 2y)}_{\text{Difference of the LHS}}=\underbrace{28-4}_{\text{Difference of the RHS}}

This can be simplified into


6y=24 \iff y=4

Now you can plug this value for
y in one of the two equations, and solve it for
x.

User Lavanna
by
6.9k points
4 votes

Answer:

(-
(4)/(3), 4 )

Explanation:

Given the 2 equations

3x + 8y = 28 → (1)

3x + 2y = 4 → (2)

Subtracting (2) from (1) term by term will eliminate the x- term

(3x - 3x) + (8y - 2y) = (28 - 4), that is

6y = 24 ( divide both sides by 6 )

y = 4

Substitute y = 4 into either of the 2 equations and solve for x

Substituting into (1)

3x + 8(4) = 28

3x + 32 = 28 ( subtract 32 from both sides )

3x = - 4 ( divide both sides by 3 )

x = -
(4)/(3)

Solution is (-
(4)/(3), 4 )

User Gustavo Morales
by
8.9k points

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