Question

3x + 8y = 28
3x + 2y = 4
Find both the x and y coordinates

Answer 1

If you subtract the two equations you get

`\underbrace{(3x + 8y)-(3x + 2y)}_{\text{Difference of the LHS}}=\underbrace{28-4}_{\text{Difference of the RHS}}`

This can be simplified into

`6y=24 \iff y=4`

Now you can plug this value for
`y` in one of the two equations, and solve it for
`x`.

Answer 2

(-
`(4)/(3)`, 4 )

Explanation:

Given the 2 equations

3x + 8y = 28 → (1)

3x + 2y = 4 → (2)

Subtracting (2) from (1) term by term will eliminate the x- term

(3x - 3x) + (8y - 2y) = (28 - 4), that is

6y = 24 ( divide both sides by 6 )

y = 4

Substitute y = 4 into either of the 2 equations and solve for x

Substituting into (1)

3x + 8(4) = 28

3x + 32 = 28 ( subtract 32 from both sides )

3x = - 4 ( divide both sides by 3 )

x = -
`(4)/(3)`

Solution is (-
`(4)/(3)`, 4 )